80.65+19.61y(0.006482-y)=100-9.76y(1+y)

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Solution for 80.65+19.61y(0.006482-y)=100-9.76y(1+y) equation:



80.65+19.61y(0.006482-y)=100-9.76y(1+y)
We move all terms to the left:
80.65+19.61y(0.006482-y)-(100-9.76y(1+y))=0
We add all the numbers together, and all the variables
19.61y(-1y+0.006482)-(100-9.76y(y+1))+80.65=0
We multiply parentheses
-19y^2+0.123158y-(100-9.76y(y+1))+80.65=0
We calculate terms in parentheses: -(100-9.76y(y+1)), so:
100-9.76y(y+1)
determiningTheFunctionDomain -9.76y(y+1)+100
We multiply parentheses
-9y^2-9y+100
Back to the equation:
-(-9y^2-9y+100)
We get rid of parentheses
-19y^2+9y^2+9y+0.123158y-100+80.65=0
We add all the numbers together, and all the variables
-10y^2+9.123158y-19.35=0
a = -10; b = 9.123158; c = -19.35;
Δ = b2-4ac
Δ = 9.1231582-4·(-10)·(-19.35)
Δ = -690.76798810704
Delta is less than zero, so there is no solution for the equation

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