If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1;64;1;16;0;0
1;64;1;32;0;0
1;16;1;32;0;0
ln(x^2-(2*x)+2)
1;16;0;0;0;0
| -6+3(1+5x)=72 | | x+11.15=18.15 | | P/11=9 | | a=2x+px | | x^2+36x+36=-5 | | -6-2/3y | | x+18.15=11.15 | | (x^2-2x-8)(-x^2+3x-5)=0 | | 18x^2-32=1x-18x^2 | | 5.5x=66 | | -2=m/2 | | ln(6-x)-2lnx=0 | | x-18.15=15.11 | | 18=-2m-7m | | 83=8x | | 4(m-2)=22 | | 1234=2353 | | 3d+1=2x+10 | | -n-2n=6 | | 1x-8=56 | | 0.43=3.01 | | (-4x^2-5x-1)(4x^2-6x-2)=0 | | 5x+45=1.70 | | 6x+10y=-90 | | 6cos^2(3x)-7cos(3x)-3=0 | | -3.6k=-10.8 | | 1x+4=68 | | y+9x=0 | | 3x+4(x-8)=2x+3 | | 4x-12=x^2 | | -11x-17=72 | | Sin(x)=0.465 |