803/80=-3/4t+4/5t+10

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Solution for 803/80=-3/4t+4/5t+10 equation:


t in (-oo:+oo)

803/80 = (-3/4)*t+(4/5)*t+10 // - (-3/4)*t+(4/5)*t+10

803/80-((-3/4)*t)-((4/5)*t)-10 = 0

(3/4)*t+(-4/5)*t+803/80-10 = 0

3/80-1/20*t = 0 // - 3/80

-1/20*t = -3/80 // : -1/20

t = -3/80/(-1/20)

t = 3/4

t = 3/4

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