80=(240-16t)/(t+3)

Solution for 80=(240-16t)/(t+3) equation:

80=(240-16t)/(t+3)

We move all terms to the left:

80-((240-16t)/(t+3))=0


Domain of the equation: (t+3))!=0

t∈R


We add all the numbers together, and all the variables

-((-16t+240)/(t+3))+80=0

We multiply all the terms by the denominator


-((-16t+240)+80*(t+3))=0


We calculate terms in parentheses: -((-16t+240)+80*(t+3)), so:

(-16t+240)+80*(t+3)

We multiply parentheses

(-16t+240)+80t+240

We get rid of parentheses

-16t+80t+240+240

We add all the numbers together, and all the variables

64t+480

Back to the equation:

-(64t+480)


We get rid of parentheses

-64t-480=0

We move all terms containing t to the left, all other terms to the right

-64t=480

t=480/-64

t=-7+1/2