80=(8+x)(8-x)

Solution for 80=(8+x)(8-x) equation:

80=(8+x)(8-x)

We move all terms to the left:

80-((8+x)(8-x))=0

We add all the numbers together, and all the variables

-((x+8)(-1x+8))+80=0

We multiply parentheses ..

-((-1x^2+8x-8x+64))+80=0


We calculate terms in parentheses: -((-1x^2+8x-8x+64)), so:

(-1x^2+8x-8x+64)

We get rid of parentheses

-1x^2+8x-8x+64

We add all the numbers together, and all the variables

-1x^2+64

Back to the equation:

-(-1x^2+64)


We get rid of parentheses

1x^2-64+80=0

We add all the numbers together, and all the variables

x^2+16=0

a = 1; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·1·16
Δ = -64
Delta is less than zero, so there is no solution for the equation