80=(9/5)c+35

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Solution for 80=(9/5)c+35 equation: 



80=(9/5)c+35

We move all terms to the left:

80-((9/5)c+35)=0



Domain of the equation: 5)c+35)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-((+9/5)c+35)+80=0

We multiply all the terms by the denominator


-((+9+80*5)c+35)=0



We calculate terms in parentheses: -((+9+80*5)c+35), so:

(+9+80*5)c+35

We add all the numbers together, and all the variables

409c+35

Back to the equation:

-(409c+35)



We get rid of parentheses

-409c-35=0

We move all terms containing c to the left, all other terms to the right

-409c=35

c=35/-409

c=-35/409

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