80=-5(-3b-1)+3(4b-2)

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Solution for 80=-5(-3b-1)+3(4b-2) equation: 



80=-5(-3b-1)+3(4b-2)

We move all terms to the left:

80-(-5(-3b-1)+3(4b-2))=0



We calculate terms in parentheses: -(-5(-3b-1)+3(4b-2)), so:

-5(-3b-1)+3(4b-2)

We multiply parentheses

15b+12b+5-6

We add all the numbers together, and all the variables

27b-1

Back to the equation:

-(27b-1)



We get rid of parentheses

-27b+1+80=0

We add all the numbers together, and all the variables

-27b+81=0

We move all terms containing b to the left, all other terms to the right

-27b=-81

b=-81/-27

b=+3

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