80=10(t-2)

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Solution for 80=10(t-2) equation: 



80=10(t-2)

We move all terms to the left:

80-(10(t-2))=0



We calculate terms in parentheses: -(10(t-2)), so:

10(t-2)

We multiply parentheses

10t-20

Back to the equation:

-(10t-20)



We get rid of parentheses

-10t+20+80=0

We add all the numbers together, and all the variables

-10t+100=0

We move all terms containing t to the left, all other terms to the right

-10t=-100

t=-100/-10

t=+10

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