80=2(5z)

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Solution for 80=2(5z) equation: 



80=2(5z)

We move all terms to the left:

80-(2(5z))=0

determiningTheFunctionDomain
-25z+80=0

We move all terms containing z to the left, all other terms to the right

-25z=-80

z=-80/-25

z=3+1/5

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