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80=2+2(2/3)L
We move all terms to the left:
80-(2+2(2/3)L)=0
Domain of the equation: 3)L)!=0We add all the numbers together, and all the variables
L!=0/1
L!=0
L∈R
-(2+2(+2/3)L)+80=0
We multiply all the terms by the denominator
-(2+2(+2+80*3)L)=0
We calculate terms in parentheses: -(2+2(+2+80*3)L), so:We get rid of parentheses
2+2(+2+80*3)L
determiningTheFunctionDomain 2(+2+80*3)L+2
We add all the numbers together, and all the variables
2242L+2
Back to the equation:
-(2242L+2)
-2242L-2=0
We move all terms containing L to the left, all other terms to the right
-2242L=2
L=2/-2242
L=-1/1121
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