80=4(12+b)

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Solution for 80=4(12+b) equation:



80=4(12+b)
We move all terms to the left:
80-(4(12+b))=0
We add all the numbers together, and all the variables
-(4(b+12))+80=0
We calculate terms in parentheses: -(4(b+12)), so:
4(b+12)
We multiply parentheses
4b+48
Back to the equation:
-(4b+48)
We get rid of parentheses
-4b-48+80=0
We add all the numbers together, and all the variables
-4b+32=0
We move all terms containing b to the left, all other terms to the right
-4b=-32
b=-32/-4
b=+8

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