80=4(12+b)

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Solution for 80=4(12+b) equation: 



80=4(12+b)

We move all terms to the left:

80-(4(12+b))=0

We add all the numbers together, and all the variables

-(4(b+12))+80=0



We calculate terms in parentheses: -(4(b+12)), so:

4(b+12)

We multiply parentheses

4b+48

Back to the equation:

-(4b+48)



We get rid of parentheses

-4b-48+80=0

We add all the numbers together, and all the variables

-4b+32=0

We move all terms containing b to the left, all other terms to the right

-4b=-32

b=-32/-4

b=+8

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