80=40+10/3x

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Solution for 80=40+10/3x equation: 



80=40+10/3x

We move all terms to the left:

80-(40+10/3x)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(10/3x+40)+80=0

We get rid of parentheses

-10/3x-40+80=0

We multiply all the terms by the denominator


-40*3x+80*3x-10=0

Wy multiply elements

-120x+240x-10=0

We add all the numbers together, and all the variables

120x-10=0

We move all terms containing x to the left, all other terms to the right

120x=10

x=10/120

x=1/12

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