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80=5t*t
We move all terms to the left:
80-(5t*t)=0
We add all the numbers together, and all the variables
-(+5t*t)+80=0
We get rid of parentheses
-5t*t+80=0
Wy multiply elements
-5t^2+80=0
a = -5; b = 0; c = +80;
Δ = b2-4ac
Δ = 02-4·(-5)·80
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*-5}=\frac{-40}{-10} =+4 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*-5}=\frac{40}{-10} =-4 $
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