80=8t+16t(2)

Solution for 80=8t+16t(2) equation:

80=8t+16t(2)

We move all terms to the left:

80-(8t+16t(2))=0

We add all the numbers together, and all the variables

-(+8t+16t^2)+80=0

We get rid of parentheses

-16t^2-8t+80=0

a = -16; b = -8; c = +80;
Δ = b2-4ac
Δ = -82-4·(-16)·80
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-72}{2*-16}=\frac{-64}{-32}
=+2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+72}{2*-16}=\frac{80}{-32}
=-2+1/2
$