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80=x2+2x
We move all terms to the left:
80-(x2+2x)=0
We add all the numbers together, and all the variables
-(+x^2+2x)+80=0
We get rid of parentheses
-x^2-2x+80=0
We add all the numbers together, and all the variables
-1x^2-2x+80=0
a = -1; b = -2; c = +80;
Δ = b2-4ac
Δ = -22-4·(-1)·80
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*-1}=\frac{-16}{-2} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*-1}=\frac{20}{-2} =-10 $
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