80x-10(3-4x)=-45+6(x-7)

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Solution for 80x-10(3-4x)=-45+6(x-7) equation: 



80x-10(3-4x)=-45+6(x-7)

We move all terms to the left:

80x-10(3-4x)-(-45+6(x-7))=0

We add all the numbers together, and all the variables

80x-10(-4x+3)-(-45+6(x-7))=0

We multiply parentheses

80x+40x-(-45+6(x-7))-30=0



We calculate terms in parentheses: -(-45+6(x-7)), so:

-45+6(x-7)

determiningTheFunctionDomain
6(x-7)-45

We multiply parentheses

6x-42-45

We add all the numbers together, and all the variables

6x-87

Back to the equation:

-(6x-87)



We add all the numbers together, and all the variables

120x-(6x-87)-30=0

We get rid of parentheses

120x-6x+87-30=0

We add all the numbers together, and all the variables

114x+57=0

We move all terms containing x to the left, all other terms to the right

114x=-57

x=-57/114

x=-1/2

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