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80x=4x^2
We move all terms to the left:
80x-(4x^2)=0
determiningTheFunctionDomain -4x^2+80x=0
a = -4; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-4)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-4}=\frac{-160}{-8} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-4}=\frac{0}{-8} =0 $
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