81(b-1)+63=9(9b-2)

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Solution for 81(b-1)+63=9(9b-2) equation:


Simplifying
81(b + -1) + 63 = 9(9b + -2)

Reorder the terms:
81(-1 + b) + 63 = 9(9b + -2)
(-1 * 81 + b * 81) + 63 = 9(9b + -2)
(-81 + 81b) + 63 = 9(9b + -2)

Reorder the terms:
-81 + 63 + 81b = 9(9b + -2)

Combine like terms: -81 + 63 = -18
-18 + 81b = 9(9b + -2)

Reorder the terms:
-18 + 81b = 9(-2 + 9b)
-18 + 81b = (-2 * 9 + 9b * 9)
-18 + 81b = (-18 + 81b)

Add '18' to each side of the equation.
-18 + 18 + 81b = -18 + 18 + 81b

Combine like terms: -18 + 18 = 0
0 + 81b = -18 + 18 + 81b
81b = -18 + 18 + 81b

Combine like terms: -18 + 18 = 0
81b = 0 + 81b
81b = 81b

Add '-81b' to each side of the equation.
81b + -81b = 81b + -81b

Combine like terms: 81b + -81b = 0
0 = 81b + -81b

Combine like terms: 81b + -81b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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