81-108=-6(-4y)-13(2y)+y

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Solution for 81-108=-6(-4y)-13(2y)+y equation: 



81-108=-6(-4y)-13(2y)+y

We move all terms to the left:

81-108-(-6(-4y)-13(2y)+y)=0

We add all the numbers together, and all the variables

-(-6(-4y)-132y+y)-27=0



We calculate terms in parentheses: -(-6(-4y)-132y+y), so:

-6(-4y)-132y+y

We add all the numbers together, and all the variables

-131y-6(-4y)

We multiply parentheses

-131y+24y

We add all the numbers together, and all the variables

-107y

Back to the equation:

-(-107y)



We get rid of parentheses

107y-27=0

We move all terms containing y to the left, all other terms to the right

107y=27

y=27/107

y=27/107

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