8100=1/2(2x)(x+2x)

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Solution for 8100=1/2(2x)(x+2x) equation: 



8100=1/2(2x)(x+2x)

We move all terms to the left:

8100-(1/2(2x)(x+2x))=0



Domain of the equation: 22x(x+2x))!=0

x∈R



We add all the numbers together, and all the variables

-(1/22x(+3x))+8100=0

We multiply all the terms by the denominator


-(1+8100*22x(+3x))=0



We calculate terms in parentheses: -(1+8100*22x(+3x)), so:

1+8100*22x(+3x)

determiningTheFunctionDomain
8100*22x(+3x)+1

Wy multiply elements

178200x(++1

We use the square of the difference formula

178200x(+1

Back to the equation:

-(178200x(+1)



We add all the numbers together, and all the variables

-(178200x1=0

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