81=9/5c+32

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Solution for 81=9/5c+32 equation:



81=9/5c+32
We move all terms to the left:
81-(9/5c+32)=0
Domain of the equation: 5c+32)!=0
c∈R
We get rid of parentheses
-9/5c-32+81=0
We multiply all the terms by the denominator
-32*5c+81*5c-9=0
Wy multiply elements
-160c+405c-9=0
We add all the numbers together, and all the variables
245c-9=0
We move all terms containing c to the left, all other terms to the right
245c=9
c=9/245
c=9/245

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