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81=x(2x+x)
We move all terms to the left:
81-(x(2x+x))=0
We add all the numbers together, and all the variables
-(x(+3x))+81=0
We calculate terms in parentheses: -(x(+3x)), so:a = -3; b = 0; c = +81;
x(+3x)
We multiply parentheses
3x^2
Back to the equation:
-(3x^2)
Δ = b2-4ac
Δ = 02-4·(-3)·81
Δ = 972
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{972}=\sqrt{324*3}=\sqrt{324}*\sqrt{3}=18\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{3}}{2*-3}=\frac{0-18\sqrt{3}}{-6} =-\frac{18\sqrt{3}}{-6} =-\frac{3\sqrt{3}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{3}}{2*-3}=\frac{0+18\sqrt{3}}{-6} =\frac{18\sqrt{3}}{-6} =\frac{3\sqrt{3}}{-1} $
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