81x+9x2=0

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Solution for 81x+9x2=0 equation: 



81x+9x^2=0

a = 9; b = 81; c = 0;
Δ = b2-4ac
Δ = 812-4·9·0
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-81}{2*9}=\frac{-162}{18}
=-9
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+81}{2*9}=\frac{0}{18}
=0
$

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