81x2+72x+16=0

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Solution for 81x2+72x+16=0 equation: 



81x^2+72x+16=0

a = 81; b = 72; c = +16;
Δ = b2-4ac
Δ = 722-4·81·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-72}{162}=-4/9$

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