82=(2x-8)+(3x-12)+x

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Solution for 82=(2x-8)+(3x-12)+x equation: 



82=(2x-8)+(3x-12)+x

We move all terms to the left:

82-((2x-8)+(3x-12)+x)=0



We calculate terms in parentheses: -((2x-8)+(3x-12)+x), so:

(2x-8)+(3x-12)+x

We add all the numbers together, and all the variables

x+(2x-8)+(3x-12)

We get rid of parentheses

x+2x+3x-8-12

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

-6x+20+82=0

We add all the numbers together, and all the variables

-6x+102=0

We move all terms containing x to the left, all other terms to the right

-6x=-102

x=-102/-6

x=+17

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