82=1+3(3b+3)

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Solution for 82=1+3(3b+3) equation: 



82=1+3(3b+3)

We move all terms to the left:

82-(1+3(3b+3))=0



We calculate terms in parentheses: -(1+3(3b+3)), so:

1+3(3b+3)

determiningTheFunctionDomain
3(3b+3)+1

We multiply parentheses

9b+9+1

We add all the numbers together, and all the variables

9b+10

Back to the equation:

-(9b+10)



We get rid of parentheses

-9b-10+82=0

We add all the numbers together, and all the variables

-9b+72=0

We move all terms containing b to the left, all other terms to the right

-9b=-72

b=-72/-9

b=+8

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