83.33+15.63y(0.006835-y)=100-11.24y(1+y)

Solution for 83.33+15.63y(0.006835-y)=100-11.24y(1+y) equation:

83.33+15.63y(0.006835-y)=100-11.24y(1+y)

We move all terms to the left:

83.33+15.63y(0.006835-y)-(100-11.24y(1+y))=0

We add all the numbers together, and all the variables

15.63y(-1y+0.006835)-(100-11.24y(y+1))+83.33=0

We multiply parentheses

-15y^2+0.102525y-(100-11.24y(y+1))+83.33=0


We calculate terms in parentheses: -(100-11.24y(y+1)), so:

100-11.24y(y+1)

determiningTheFunctionDomain
-11.24y(y+1)+100

We multiply parentheses

-11y^2-11y+100

Back to the equation:

-(-11y^2-11y+100)


We get rid of parentheses

-15y^2+11y^2+11y+0.102525y-100+83.33=0

We add all the numbers together, and all the variables

-4y^2+11.102525y-16.67=0

a = -4; b = 11.102525; c = -16.67;
Δ = b2-4ac
Δ = 11.1025252-4·(-4)·(-16.67)
Δ = -143.45393862438
Delta is less than zero, so there is no solution for the equation