84=(1)/(2)x(2+x)

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Solution for 84=(1)/(2)x(2+x) equation:



84=(1)/(2)x(2+x)
We move all terms to the left:
84-((1)/(2)x(2+x))=0
Domain of the equation: 2x(2+x))!=0
x∈R
We add all the numbers together, and all the variables
-(1/2x(x+2))+84=0
We multiply all the terms by the denominator
-(1+84*2x(x+2))=0
We calculate terms in parentheses: -(1+84*2x(x+2)), so:
1+84*2x(x+2)
determiningTheFunctionDomain 84*2x(x+2)+1
Wy multiply elements
168x(x+1
Back to the equation:
-(168x(x+1)
We calculate terms in parentheses: -(168x(x+1), so:
168x(x+1
We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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We calculate terms in parentheses: -(168x(x+1), so:
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