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84=18t^2+7t
We move all terms to the left:
84-(18t^2+7t)=0
We get rid of parentheses
-18t^2-7t+84=0
a = -18; b = -7; c = +84;
Δ = b2-4ac
Δ = -72-4·(-18)·84
Δ = 6097
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{6097}}{2*-18}=\frac{7-\sqrt{6097}}{-36} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{6097}}{2*-18}=\frac{7+\sqrt{6097}}{-36} $
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