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84=x(2x+5)
We move all terms to the left:
84-(x(2x+5))=0
We calculate terms in parentheses: -(x(2x+5)), so:We get rid of parentheses
x(2x+5)
We multiply parentheses
2x^2+5x
Back to the equation:
-(2x^2+5x)
-2x^2-5x+84=0
a = -2; b = -5; c = +84;
Δ = b2-4ac
Δ = -52-4·(-2)·84
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{697}}{2*-2}=\frac{5-\sqrt{697}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{697}}{2*-2}=\frac{5+\sqrt{697}}{-4} $
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