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85=w(w+12)
We move all terms to the left:
85-(w(w+12))=0
We calculate terms in parentheses: -(w(w+12)), so:We get rid of parentheses
w(w+12)
We multiply parentheses
w^2+12w
Back to the equation:
-(w^2+12w)
-w^2-12w+85=0
We add all the numbers together, and all the variables
-1w^2-12w+85=0
a = -1; b = -12; c = +85;
Δ = b2-4ac
Δ = -122-4·(-1)·85
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-22}{2*-1}=\frac{-10}{-2} =+5 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+22}{2*-1}=\frac{34}{-2} =-17 $
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