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88/4x+12=36/2x
We move all terms to the left:
88/4x+12-(36/2x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
88/4x-(+36/2x)+12=0
We get rid of parentheses
88/4x-36/2x+12=0
We calculate fractions
176x/8x^2+(-144x)/8x^2+12=0
We multiply all the terms by the denominator
176x+(-144x)+12*8x^2=0
Wy multiply elements
96x^2+176x+(-144x)=0
We get rid of parentheses
96x^2+176x-144x=0
We add all the numbers together, and all the variables
96x^2+32x=0
a = 96; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·96·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{1024}=32x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*96}=\frac{-64}{192} =-1/3x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*96}=\frac{0}{192} =0
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