8=(2x)/(0.2-x)

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Solution for 8=(2x)/(0.2-x) equation:



8=(2x)/(0.2-x)
We move all terms to the left:
8-((2x)/(0.2-x))=0
Domain of the equation: (0.2-x))!=0
We move all terms containing x to the left, all other terms to the right
-x)!=-0.2
x!=-0.2/1
x!=-0.2
x∈R
We add all the numbers together, and all the variables
-(2x/(-1x+0.2))+8=0
We multiply all the terms by the denominator
-(2x+8*(-1x+0.2))=0
We calculate terms in parentheses: -(2x+8*(-1x+0.2)), so:
2x+8*(-1x+0.2)
We multiply parentheses
2x-8x+1.6
We add all the numbers together, and all the variables
-6x+1.6
Back to the equation:
-(-6x+1.6)
We get rid of parentheses
6x-1.6=0
We move all terms containing x to the left, all other terms to the right
6x=1.6
x=1.6/6
x=1/3.75

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