8=(3/4)1a+12-1a+4

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Solution for 8=(3/4)1a+12-1a+4 equation: 



8=(3/4)1a+12-1a+4

We move all terms to the left:

8-((3/4)1a+12-1a+4)=0



Domain of the equation: 4)1a+12-1a+4)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

-((+3/4)1a+12-1a+4)+8=0

We multiply all the terms by the denominator


-((+3+8*4)1a+12-1a+4)=0



We calculate terms in parentheses: -((+3+8*4)1a+12-1a+4), so:

(+3+8*4)1a+12-1a+4

determiningTheFunctionDomain
(+3+8*4)1a-1a+12+4

We add all the numbers together, and all the variables

351a-1a+12+4

We add all the numbers together, and all the variables

350a+16

Back to the equation:

-(350a+16)



We get rid of parentheses

-350a-16=0

We move all terms containing a to the left, all other terms to the right

-350a=16

a=16/-350

a=-8/175

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