8=(3/4)a+12-a+4

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Solution for 8=(3/4)a+12-a+4 equation: 



8=(3/4)a+12-a+4

We move all terms to the left:

8-((3/4)a+12-a+4)=0



Domain of the equation: 4)a+12-a+4)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

-((+3/4)a+12-a+4)+8=0

We multiply all the terms by the denominator


-((+3+8*4)a+12-a+4)=0



We calculate terms in parentheses: -((+3+8*4)a+12-a+4), so:

(+3+8*4)a+12-a+4

determiningTheFunctionDomain
(+3+8*4)a-a+12+4

We add all the numbers together, and all the variables

35a-a+12+4

We add all the numbers together, and all the variables

34a+16

Back to the equation:

-(34a+16)



We get rid of parentheses

-34a-16=0

We move all terms containing a to the left, all other terms to the right

-34a=16

a=16/-34

a=-8/17

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