8=(3/4a+12-a+4

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Solution for 8=(3/4a+12-a+4 equation: 



8=(3/4a+12-a+4

We move all terms to the left:

8-((3/4a+12-a+4)=0



Domain of the equation: 4a+12-a+4)+8!=0

We move all terms containing a to the left, all other terms to the right

4a-a+4)+8!=-12

a∈R



We add all the numbers together, and all the variables

-((-1a+3/4a+16)+8=0

We multiply all the terms by the denominator


-((-1a+3=0

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