8=(6-9x)/(3-x)

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Solution for 8=(6-9x)/(3-x) equation: 



8=(6-9x)/(3-x)

We move all terms to the left:

8-((6-9x)/(3-x))=0



Domain of the equation: (3-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

-((-9x+6)/(-1x+3))+8=0

We multiply all the terms by the denominator


-((-9x+6)+8*(-1x+3))=0



We calculate terms in parentheses: -((-9x+6)+8*(-1x+3)), so:

(-9x+6)+8*(-1x+3)

We multiply parentheses

(-9x+6)-8x+24

We get rid of parentheses

-9x-8x+6+24

We add all the numbers together, and all the variables

-17x+30

Back to the equation:

-(-17x+30)



We get rid of parentheses

17x-30=0

We move all terms containing x to the left, all other terms to the right

17x=30

x=30/17

x=1+13/17

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