8=-18+(3/8)(16-40x

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Solution for 8=-18+(3/8)(16-40x equation: 



8=-18+(3/8)(16-40x

We move all terms to the left:

8-(-18+(3/8)(16-40x)=0



Domain of the equation: 8)(16-40x)+8!=0

x∈R



We add all the numbers together, and all the variables

-(-18+(+3/8)(-40x+16)+8=0

We multiply parentheses ..

-(-18+(-120x^2+3/8*16)+8=0

We multiply all the terms by the denominator


-(-18+(-120x^2+3=0

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