8=-18+3/8(16-40h)

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Solution for 8=-18+3/8(16-40h) equation: 



8=-18+3/8(16-40h)

We move all terms to the left:

8-(-18+3/8(16-40h))=0



Domain of the equation: 8(16-40h))!=0

h∈R



We add all the numbers together, and all the variables

-(-18+3/8(-40h+16))+8=0

We multiply all the terms by the denominator


-(-18+3+8*8(-40h+16))=0



We calculate terms in parentheses: -(-18+3+8*8(-40h+16)), so:

-18+3+8*8(-40h+16)

determiningTheFunctionDomain
8*8(-40h+16)-18+3

We add all the numbers together, and all the variables

8*8(-40h+16)-15

Wy multiply elements

64h(--15

We use the square of the difference formula

64h(+15

Back to the equation:

-(64h(+15)



We add all the numbers together, and all the variables

-(64h15=0

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