8=-18+3/8(16-40x)

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Solution for 8=-18+3/8(16-40x) equation: 



8=-18+3/8(16-40x)

We move all terms to the left:

8-(-18+3/8(16-40x))=0



Domain of the equation: 8(16-40x))!=0

x∈R



We add all the numbers together, and all the variables

-(-18+3/8(-40x+16))+8=0

We multiply all the terms by the denominator


-(-18+3+8*8(-40x+16))=0



We calculate terms in parentheses: -(-18+3+8*8(-40x+16)), so:

-18+3+8*8(-40x+16)

determiningTheFunctionDomain
8*8(-40x+16)-18+3

We add all the numbers together, and all the variables

8*8(-40x+16)-15

Wy multiply elements

64x(--15

We use the square of the difference formula

64x(+15

Back to the equation:

-(64x(+15)



We add all the numbers together, and all the variables

-(64x15=0

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