8=-18+3/8-(16-40n)

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Solution for 8=-18+3/8-(16-40n) equation: 



8=-18+3/8-(16-40n)

We move all terms to the left:

8-(-18+3/8-(16-40n))=0



Domain of the equation: 8-(16-40n))!=0

We move all terms containing n to the left, all other terms to the right

-(16-40n))!=-8

n∈R



We add all the numbers together, and all the variables

-(-18+3/8-(-40n+16))+8=0

We multiply all the terms by the denominator


-(-18+3+8*8-(-40n+16))=0



We calculate terms in parentheses: -(-18+3+8*8-(-40n+16)), so:

-18+3+8*8-(-40n+16)

determiningTheFunctionDomain
-(-40n+16)-18+3+8*8

We add all the numbers together, and all the variables

-(-40n+16)+49

We get rid of parentheses

40n-16+49

We add all the numbers together, and all the variables

40n+33

Back to the equation:

-(40n+33)



We get rid of parentheses

-40n-33=0

We move all terms containing n to the left, all other terms to the right

-40n=33

n=33/-40

n=-33/40

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