8=-2(-8+4x)+8(-7x-1)

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Solution for 8=-2(-8+4x)+8(-7x-1) equation: 



8=-2(-8+4x)+8(-7x-1)

We move all terms to the left:

8-(-2(-8+4x)+8(-7x-1))=0

We add all the numbers together, and all the variables

-(-2(4x-8)+8(-7x-1))+8=0



We calculate terms in parentheses: -(-2(4x-8)+8(-7x-1)), so:

-2(4x-8)+8(-7x-1)

We multiply parentheses

-8x-56x+16-8

We add all the numbers together, and all the variables

-64x+8

Back to the equation:

-(-64x+8)



We get rid of parentheses

64x-8+8=0

We add all the numbers together, and all the variables

64x=0

x=0/64

x=0

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