8=-2(y-6)+10

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Solution for 8=-2(y-6)+10 equation: 



8=-2(y-6)+10

We move all terms to the left:

8-(-2(y-6)+10)=0



We calculate terms in parentheses: -(-2(y-6)+10), so:

-2(y-6)+10

We multiply parentheses

-2y+12+10

We add all the numbers together, and all the variables

-2y+22

Back to the equation:

-(-2y+22)



We get rid of parentheses

2y-22+8=0

We add all the numbers together, and all the variables

2y-14=0

We move all terms containing y to the left, all other terms to the right

2y=14

y=14/2

y=7

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