8=-4y+2(y-2)

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Solution for 8=-4y+2(y-2) equation: 



8=-4y+2(y-2)

We move all terms to the left:

8-(-4y+2(y-2))=0



We calculate terms in parentheses: -(-4y+2(y-2)), so:

-4y+2(y-2)

We multiply parentheses

-4y+2y-4

We add all the numbers together, and all the variables

-2y-4

Back to the equation:

-(-2y-4)



We get rid of parentheses

2y+4+8=0

We add all the numbers together, and all the variables

2y+12=0

We move all terms containing y to the left, all other terms to the right

2y=-12

y=-12/2

y=-6

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