8=-8(1+x)+4(6x-4)

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Solution for 8=-8(1+x)+4(6x-4) equation: 



8=-8(1+x)+4(6x-4)

We move all terms to the left:

8-(-8(1+x)+4(6x-4))=0

We add all the numbers together, and all the variables

-(-8(x+1)+4(6x-4))+8=0



We calculate terms in parentheses: -(-8(x+1)+4(6x-4)), so:

-8(x+1)+4(6x-4)

We multiply parentheses

-8x+24x-8-16

We add all the numbers together, and all the variables

16x-24

Back to the equation:

-(16x-24)



We get rid of parentheses

-16x+24+8=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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