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8=1/3(9q+6)
We move all terms to the left:
8-(1/3(9q+6))=0
Domain of the equation: 3(9q+6))!=0We multiply all the terms by the denominator
q∈R
-(1+8*3(9q+6))=0
We calculate terms in parentheses: -(1+8*3(9q+6)), so:We add all the numbers together, and all the variables
1+8*3(9q+6)
determiningTheFunctionDomain 8*3(9q+6)+1
Wy multiply elements
24q(9+1
Back to the equation:
-(24q(9+1)
-(24q10=0
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