8=1/3(a+5)

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Solution for 8=1/3(a+5) equation:



8=1/3(a+5)
We move all terms to the left:
8-(1/3(a+5))=0
Domain of the equation: 3(a+5))!=0
a∈R
We multiply all the terms by the denominator
-(1+8*3(a+5))=0
We calculate terms in parentheses: -(1+8*3(a+5)), so:
1+8*3(a+5)
determiningTheFunctionDomain 8*3(a+5)+1
Wy multiply elements
24a(a+1
Back to the equation:
-(24a(a+1)
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
24a(a+1
We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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We calculate terms in parentheses: -(24a(a+1), so:
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