8=11+3(t-2)

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Solution for 8=11+3(t-2) equation: 



8=11+3(t-2)

We move all terms to the left:

8-(11+3(t-2))=0



We calculate terms in parentheses: -(11+3(t-2)), so:

11+3(t-2)

determiningTheFunctionDomain
3(t-2)+11

We multiply parentheses

3t-6+11

We add all the numbers together, and all the variables

3t+5

Back to the equation:

-(3t+5)



We get rid of parentheses

-3t-5+8=0

We add all the numbers together, and all the variables

-3t+3=0

We move all terms containing t to the left, all other terms to the right

-3t=-3

t=-3/-3

t=1

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