8=2(x-3)-5(x-4)

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Solution for 8=2(x-3)-5(x-4) equation: 



8=2(x-3)-5(x-4)

We move all terms to the left:

8-(2(x-3)-5(x-4))=0



We calculate terms in parentheses: -(2(x-3)-5(x-4)), so:

2(x-3)-5(x-4)

We multiply parentheses

2x-5x-6+20

We add all the numbers together, and all the variables

-3x+14

Back to the equation:

-(-3x+14)



We get rid of parentheses

3x-14+8=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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