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8=2/1(2x+4)
We move all terms to the left:
8-(2/1(2x+4))=0
Domain of the equation: 1(2x+4))!=0We multiply all the terms by the denominator
x∈R
-(2+8*1(2x+4))=0
We calculate terms in parentheses: -(2+8*1(2x+4)), so:We add all the numbers together, and all the variables
2+8*1(2x+4)
determiningTheFunctionDomain 8*1(2x+4)+2
Wy multiply elements
8x(2+2
Back to the equation:
-(8x(2+2)
-(8x4=0
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